Optimal. Leaf size=89 \[ -\frac{a^2 \cos ^3(c+d x)}{3 d}+\frac{3 a^2 \cos (c+d x)}{d}+\frac{3 a^2 \tan (c+d x)}{d}+\frac{2 a^2 \sec (c+d x)}{d}-\frac{a^2 \sin ^2(c+d x) \tan (c+d x)}{d}-3 a^2 x \]
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Rubi [A] time = 0.208373, antiderivative size = 89, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 8, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.296, Rules used = {2873, 2590, 14, 2591, 288, 321, 203, 270} \[ -\frac{a^2 \cos ^3(c+d x)}{3 d}+\frac{3 a^2 \cos (c+d x)}{d}+\frac{3 a^2 \tan (c+d x)}{d}+\frac{2 a^2 \sec (c+d x)}{d}-\frac{a^2 \sin ^2(c+d x) \tan (c+d x)}{d}-3 a^2 x \]
Antiderivative was successfully verified.
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Rule 2873
Rule 2590
Rule 14
Rule 2591
Rule 288
Rule 321
Rule 203
Rule 270
Rubi steps
\begin{align*} \int \sin (c+d x) (a+a \sin (c+d x))^2 \tan ^2(c+d x) \, dx &=\int \left (a^2 \sin (c+d x) \tan ^2(c+d x)+2 a^2 \sin ^2(c+d x) \tan ^2(c+d x)+a^2 \sin ^3(c+d x) \tan ^2(c+d x)\right ) \, dx\\ &=a^2 \int \sin (c+d x) \tan ^2(c+d x) \, dx+a^2 \int \sin ^3(c+d x) \tan ^2(c+d x) \, dx+\left (2 a^2\right ) \int \sin ^2(c+d x) \tan ^2(c+d x) \, dx\\ &=-\frac{a^2 \operatorname{Subst}\left (\int \frac{1-x^2}{x^2} \, dx,x,\cos (c+d x)\right )}{d}-\frac{a^2 \operatorname{Subst}\left (\int \frac{\left (1-x^2\right )^2}{x^2} \, dx,x,\cos (c+d x)\right )}{d}+\frac{\left (2 a^2\right ) \operatorname{Subst}\left (\int \frac{x^4}{\left (1+x^2\right )^2} \, dx,x,\tan (c+d x)\right )}{d}\\ &=-\frac{a^2 \sin ^2(c+d x) \tan (c+d x)}{d}-\frac{a^2 \operatorname{Subst}\left (\int \left (-1+\frac{1}{x^2}\right ) \, dx,x,\cos (c+d x)\right )}{d}-\frac{a^2 \operatorname{Subst}\left (\int \left (-2+\frac{1}{x^2}+x^2\right ) \, dx,x,\cos (c+d x)\right )}{d}+\frac{\left (3 a^2\right ) \operatorname{Subst}\left (\int \frac{x^2}{1+x^2} \, dx,x,\tan (c+d x)\right )}{d}\\ &=\frac{3 a^2 \cos (c+d x)}{d}-\frac{a^2 \cos ^3(c+d x)}{3 d}+\frac{2 a^2 \sec (c+d x)}{d}+\frac{3 a^2 \tan (c+d x)}{d}-\frac{a^2 \sin ^2(c+d x) \tan (c+d x)}{d}-\frac{\left (3 a^2\right ) \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\tan (c+d x)\right )}{d}\\ &=-3 a^2 x+\frac{3 a^2 \cos (c+d x)}{d}-\frac{a^2 \cos ^3(c+d x)}{3 d}+\frac{2 a^2 \sec (c+d x)}{d}+\frac{3 a^2 \tan (c+d x)}{d}-\frac{a^2 \sin ^2(c+d x) \tan (c+d x)}{d}\\ \end{align*}
Mathematica [A] time = 0.514425, size = 161, normalized size = 1.81 \[ -\frac{a^2 (\sin (c+d x)+1)^2 \left (\cos \left (\frac{1}{2} (c+d x)\right ) (-6 \sin (2 (c+d x))-33 \cos (c+d x)+\cos (3 (c+d x))+36 c+36 d x)-\sin \left (\frac{1}{2} (c+d x)\right ) (-6 \sin (2 (c+d x))-33 \cos (c+d x)+\cos (3 (c+d x))+36 c+36 d x+48)\right )}{12 d \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right ) \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^4} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.062, size = 148, normalized size = 1.7 \begin{align*}{\frac{1}{d} \left ({a}^{2} \left ({\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{6}}{\cos \left ( dx+c \right ) }}+ \left ({\frac{8}{3}}+ \left ( \sin \left ( dx+c \right ) \right ) ^{4}+{\frac{4\, \left ( \sin \left ( dx+c \right ) \right ) ^{2}}{3}} \right ) \cos \left ( dx+c \right ) \right ) +2\,{a}^{2} \left ({\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{5}}{\cos \left ( dx+c \right ) }}+ \left ( \left ( \sin \left ( dx+c \right ) \right ) ^{3}+3/2\,\sin \left ( dx+c \right ) \right ) \cos \left ( dx+c \right ) -3/2\,dx-3/2\,c \right ) +{a}^{2} \left ({\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{\cos \left ( dx+c \right ) }}+ \left ( 2+ \left ( \sin \left ( dx+c \right ) \right ) ^{2} \right ) \cos \left ( dx+c \right ) \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.59813, size = 132, normalized size = 1.48 \begin{align*} -\frac{{\left (\cos \left (d x + c\right )^{3} - \frac{3}{\cos \left (d x + c\right )} - 6 \, \cos \left (d x + c\right )\right )} a^{2} + 3 \,{\left (3 \, d x + 3 \, c - \frac{\tan \left (d x + c\right )}{\tan \left (d x + c\right )^{2} + 1} - 2 \, \tan \left (d x + c\right )\right )} a^{2} - 3 \, a^{2}{\left (\frac{1}{\cos \left (d x + c\right )} + \cos \left (d x + c\right )\right )}}{3 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.08702, size = 362, normalized size = 4.07 \begin{align*} -\frac{a^{2} \cos \left (d x + c\right )^{4} - 2 \, a^{2} \cos \left (d x + c\right )^{3} + 9 \, a^{2} d x - 9 \, a^{2} \cos \left (d x + c\right )^{2} - 6 \, a^{2} + 3 \,{\left (3 \, a^{2} d x - 4 \, a^{2}\right )} \cos \left (d x + c\right ) -{\left (a^{2} \cos \left (d x + c\right )^{3} + 9 \, a^{2} d x + 3 \, a^{2} \cos \left (d x + c\right )^{2} - 6 \, a^{2} \cos \left (d x + c\right ) + 6 \, a^{2}\right )} \sin \left (d x + c\right )}{3 \,{\left (d \cos \left (d x + c\right ) - d \sin \left (d x + c\right ) + d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.28154, size = 161, normalized size = 1.81 \begin{align*} -\frac{9 \,{\left (d x + c\right )} a^{2} + \frac{12 \, a^{2}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1} + \frac{2 \,{\left (3 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 6 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 18 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 3 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 8 \, a^{2}\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{3}}}{3 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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